Question

two unequal masses A and B moving along a straight line are brought to rest by equal retarding forces. If A moves twice the time as B but goes only 1/3 of the distance covered by B before coming to rest, the ratio of their velocities is

Answer 1

ATQ
T(a)=2T(b)
Dist.(a)= 3 d (b)

speed a= dist/time
=3d(b) /2T(b)

Similarly,
speed b = d(b) / T(b)

Ratio= speed(a)/speed(b)
= 3:2
Hope it helps!!