Two unequal masses are tied together with a compressed spring. When the cord is burntwith a match releasing the spring, the two masses fly apart with equal
kinetic energy
speed
momentum
acceleration
Answers
Answered by
0
Answer:
When the cord is burnt with a match releasing the spring, the two masses fly apart with equal. As Fext=0, according to the law of conservation of momentum, →P1+→P2=constant. pls thank i have to level up ☺️
Similar questions