Question

two unequal masses of 1 kg and 2kg are connected by an inextensible light string passing over a smooth pulley a force F = 20 N is applied on 1 kg block find the acceleration of either block

Answer 1

Answer:

0.13 m/s^2.

Explanation:

The two blocks are connected to each other by a single pulley so the tension that the two blocks are experiencing will be same.

So, we can write the equation for block 1 as F-T=ma where F is 20N and m is 1Kg. Again, for the second block we have T-Mg = Ma where M is 2kg and hence equating the tension from both the equation we will get that

F-ma=M(g+a).

20 - 1*a = 19.6 + 2a.

So, acceleration a will be 0.4/3 = 0.13 m/s^2.

Answer 2

Answer:

the answer is 13 m/s square

Explanation:

because the formula is f+mg-g = m1a

g- m2a = m2a

and add thode two equations