Question

Two uniform strings 'A' and 'B' made of steel
are made to vibrate under the same tension. If the
first overtone of 'A' is equal to the second overtone
of 'B' and if the radius of 'A' is twice that of 'B' the
ratio of the lengths of the string is​

Answer 1

Answer:

2:1

Explanation:

f={(1/2L) × root of ( T/ pie r^2 d) }

L is directly proportional to r

therefore, L1:L2 =rA/rB

or, L1:L2=2rB/rB

or, L1:L2= 2:1