Question

Two unit squares are chosen at random on a
chess board. Find the probability that they have
a side in common.​

Answer 1

Answer:

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Here is how to solve:

In 64 squares, there are:

(1) 4 at-corner squares, each has ONLY 2 squares each having a side in common with...

(2) 6*4 = 24 side squares, each has ONLY 3 squares such that each has a side in common with...

(3) 6*6 = 36 inner squares, each has 4 squares such that each has a side in common with...

So we have the calculation:

P = (4/64)*(2/63) + (24/64)*(3/63)+ (36/64)*(4/63)

P = 1/18

Hope this help

Tibeo - Vietnam

Answer 2

Answer:

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