Question

Two unlike charge of equal magnitude 10 mC are seprqted by 100 cm distance The electric dipole moment is ....unit​

Answer 1

Given:

Two unlike charge of equal magnitude 10 mC are separated by 100 cm distance.

To find:

Dipole moment of the charge system.

Calculation:

Electric dipole moment will be directed from the negative charge towards the positive charge.

Let us consider that -10 mC is on the left side and +10 mC is on the right side and these charges are separated by 100 cm.

Let Dipole moment be $\vec{D}$.

$\sf{ \vec{D} = \{ q \times (intercharge \: distance) \} \: \hat{i}}$

$\sf{ = > \vec{D} = (10 \times {10}^{ - 3} \:C) \times (100 \times {10}^{ -2 } \: m) \: \hat{i}}$

$\sf{ = > \vec{D} = {10}^{ - 2} \times (1) \: \hat{i} \: \: Cm}$

$\sf{ = > \vec{D} = {10}^{ - 2} \: \hat{i} \: \: Cm }$

So, final answer is:

$\boxed{ \red{ \sf{ \vec{D} = {10}^{ - 2} \: \hat{i} \: \: Cm }}}$