Question

Two unlike parallel forces are acting at a distance of 450 mm from each other. The forces
are equivalent to a single force of 90 N, which acts at a distance of 200 mm from the
greater of the two forces. Find the magnitude of the forces

Answer 1

Answer:

magnitude=d*d.÷Newton

Answer 2

Answer:

The two forces are 40 N and 50 N.

Explanation:

Let the greater force be ' x ' and smaller force be ' y ' .

Forces are 450 mm apart from each other.

The equivalent force is acting 200 mm from 'x' and magnitude is 90 N.

We are assuming the  equivalent force acts in the direction of ' x ' .

Given that two forces are parallel and unlike to each other.

So we can equate the following equations,

y - x = 90    ( equation 1 )

Now taking moment about point from where the ' x ' originates .

y * 450 = 90 * 200

y = 40 N

Putting the value of y in equation 1.

x = |- 50 N | = 50 N