Question

Two unlike parallel forces of 10kn and 5kn are 45 cm apart. if the direction of 5kn force is reversed then the resultant shifts through what distance?​

Answer 1

Answer:

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Explanation:

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Answer 2

Given,

Forces of magnitude 5k N and 10k N act 45 cm or 0.45 m apart.

the direction of the 5k N force is reversed.

To find,

The shift in the position of the resultant force when 5k N force is reversed.

Solution,

Initially let the position where the resultant force acts be $x_i$ m away from 10k N force, so the point is 0.45 - $x_i$ m away from 5k N force.

Applying the formula, Torque = force × distance

10k ($x_i$ ) = 5k (0.45 -$x_i$ )

⇒ 2 $x_i$ = 0.45 - $x_i$

⇒ $x_i$ = 0.15 m

When the 5k N force is reversed, let the resultant force act on a point $x_f$ away from the 10k N force,  so the point is 0.45 + $x_f$ m away from the 5k N force.

⇒ 10k ($x_f$) = 5k (0.45 + $x_f$)

⇒  2 $x_f$ = 0.45 + $x_f$

⇒ $x_f$ = 0.45 m

The shift = $x_f$ -  $x_i$= 0.3 m

∴ The shift in the position where the resultant acts when the 5k N force is reversed is 0.3 m or 30 cm.