Two unlike parallel forces of 40 N at 2 m apart are acting on a rod.What should be the distance between two unlike parallel forces of 10 N to nullify the effect
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Explanation:
Consider the point at which resultant of the forces will act, is 'x' m from the point A.
Thus the point is (1.5 - x) m far from the point B.
Thus, using the formula Torque = Distance x Force acting
20x=30(1.5−x)
or,2x=4.5−3x
or,5x=4.5
or, x=0.9mor90cm
Thus the resultant point will be 0.9 m or 90 cm far from point A
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