Physics, asked by qureshivarshan4, 1 day ago

two unlike parallel forces of magnitude 400n and 100n are acting in such a way that their lines of action are 150 mm apart determine the magnitude of the resultant force and the point at which it acts

Answers

Answered by danushaikh666
4

F=400-100

F=300N

400x=100(150-x)

4x+x=150

5x=150

x=30

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Answered by ishwaryam062001
0

Answer:

The magnitude of the resultant force is 460 N, and the point at which it acts is located 75 mm away from the 400 N force.

Explanation:

From the above question,

They have given :

QUESTION :

Two unlike parallel forces of magnitude 400 N and 100 N are acting in such away that their lines of action are 150 mm apart. Determine the magnitude of the resultant force and the point at which it acts.

To calculate the magnitude of the result force by using the Pythagorean theorem. The magnitude of the result force is equal to the square root of the sum of the squares of the two forces.

The distance between the two forces.

The distance between the two forces is 150 mm.

Set up a triangle with the two forces and the resultant force. Label the two forces as 400 N and 100 N. Label the resultant force as R.

To valculate the magnitude of the resultant force using the Pythagorean theorem:

                R2 = 4002 + 1002.

To solve for R.

                R = 460 N.

The point at which the resultant force acts.

The point is located 75 mm away from the 400 N force.

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