Two urns urn a has 3 distinct red balls and urn has 9 distinct blue balls
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Total no. of balls in urn A=3
Total no. of balls in urn B=9
The number of ways in which two balls from urn A and two balls from urn B can be selected =3C2×9C2
3C2=3/21=3
9C2=9/2×7=9×8×7/2×7=36
3C2×9C2=3×36
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