Question

Two vector A-3i +8j-2k and B -6i+16j+xk are such that the component of B perpendicular to
A is zero. Then the value of x will be​

Answer 1

Answer:

bekt

Explanations:

dot product of the 2vector are zero

A=3i+8j-2k

B=6i+16j+xk

A.B=0

then,

-2x=0

x=0

Answer 2

Answer:

The value of x= - 4

Explanation:

Given,

A = 3i + 8j - 2k

B = 6i + 16j + xk

The component of B is perpendicular to A is zero. Then, #A×B =0

So, by determinant method, we get,

(8x + 32)i - (3x+12)j + (48 - 48)k = 0 = 0i + 0j + 0k

==> So, (8x+32) = 0 (OR) (3x+12) = 0

==>8x = -32 3x = -12

x = -4. x = -4

Hope it helps..!!