two vector A,B are such that A vector+B vector=A vectors-B vector then find incorrect_1.A vector=0,2. Avector ×B vector=0 3.Avector=0 4.B vector=0
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Given ∣a∣=1,∣∣∣∣b∣∣∣∣=4a.b=2 and c=(2a×b)−3b
a.b=2⇒∣a∣∣b∣.cos(a,b)=2
1×4×cosθ=2
cosθ=21⇒θ=60∘ (Angle b/w a,b)
a×b=∣a∣∣b∣.sinθ=1×4×sin60=4×22=23
Given c=2a
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