Two vector both equal in magnitude have there Resultant in equal in magnitude of the eightin. Find the angle between the two vectors.
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Answer:
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Explanation:
Let θ be the angle between the two vectors A and B such that, |A| = |B|.
Therefore, R2=A2+B2+2ABcosθ
=>A2=A2+A2+2AAcosθ
=>A2=A2+A2+2AAcosθ
[∵∵ |A| = |B| = |R|]
=>A2=2A2+2A2cosθ
=>A2=2A2+2A2cosθ
=>cosθ=−12=>θ=120∘
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