Question

Two vector P and Q are in the ratio 1:3. If the angle between the two vector is 60° . Then their resultant will hv a magnitude of?

Answer 1

Answer:

Two forces P and Q are in ratio P:Q=1:2. If their resultant is at an angle tan^(-1)(( sqrt3),(2)) to vector P, then angle between P and Q is

Answer 2

Answer:

given : P/Q=1/3

           Q=3 P

to find: magnitude of resultant vector

solution: let resultant vector be R

            R=$(P^{2} +Q^{2}+2PQ cos60) ^{1/2}$

            R=$(P^{2} +9P^{2}+2 (P) (3P) 0.5) ^{1/2}$

            R=$\sqrt{13}$P

             OR

            R=$\sqrt{13}$Q/3