two vectors A (6,2,1) 4 B (3,4,-8)
find angle between two vectors. answer : theta = cos ^-3 ((18/sqrt 41 into sqrt 89))
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Apply the equation theta = tan–1(y/x) to find the angle: tan–1(1.0/–1.0) = –45 degrees. However, note that the angle must really be between 90 degrees and 180 degrees because the first vector component is negative and the second is positive.
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