Question

two vectors A ^ and B^are such that A^× B^ = C^ and A= B= C then angle between A^ and B^ is​

Answer 1

Answer:

We have,

a+b=ca+b=c ……………………(1)

Also,

|a|+|b|=|c||a|+|b|=|c| …………(2)

Square the equation, (1), we get,

(a+b).(a+b)=c.c(a+b).(a+b)=c.c

Implies,

|a|2+|b|2|+2(a.b)=|c|2|a|2+|b|2|+2(a.b)=|c|2 ……….(3)

From (2), we can get,

|a|2+|b|2|+2|a||b|=|c|2|a|2+|b|2|+2|a||b|=|c|2 ………(4)

Since the RHS’s of (3) and (4) are same, we can equate them, we get,

|a|2+|b|2|+2(a.b)=|a|2+|b|2|+2|a||b||a|2+|b|2|+2(a.b)=|a|2+|b|2|+2|a||b|

Implies,

a.b=|a||b|a.b=|a||b|

Dot Product of 2 vectors is the product of absolute values of the vectors with the cosine of angle between them. So,

|a||b|cosx=|a||b||a||b|cosx=|a||b|

Answer 2

Answer:

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