Two vectors A and B are such that Ā+B=C and A^2+ B^2 = C^2. If theta
is the angle between positive
direction of A and B then theta is equal to
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Explanation:
given: A+B=C and A^2+B^2=C^2
to find: Φ b/w them
find: putting value of C from 1 in eq. 2
A^2+B^2=(A+B)^2
A^2+B^2=A^2+B^2+2A.B
2AB=0
AB=0
|A||B|COSΦ=0. (because, X.Y= |X||Y|COSΦ)
COSΦ=0
COSΦ=COSπ/2
Φ=π/2
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