Question

Two vectors are given as vector =2i+3j+5 and force F=3i-2j+4. Find out the torque acting on it.​

Answer 1

Answer:

$Torque = 22\hat{i}+7\hat{j}-13\hat{k}$

Step-by-step explanation:

Torque is given by the cross product of the force vector $(\vec{F})$ and the line vector from the point of rotation to the point of action of the force $(\vec{r})$

$\vec{r}=2\hat{i}+3\hat{j}+5\hat{k}\\\\\vec{F}=3\hat{i}-2\hat{j}+4\hat{k}\\\\\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\2&3&5\\3&-2&4\end{array}\right]$

$[3*4 - (-2)*5]\hat{i}+[3*5-2*4]\hat{j}+[2*(-2)-3*3]\hat{k}\\\\22\hat{i}+7\hat{j}-13\hat{k} = Torque$