Two vectors are given by vector a=-2i+j-3k and vector b=5i+3j-2k . If 3a+2b-c=0 then third vector c is
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Explanation:
put vector a and vector b in the given eqn...
3(2i +j -3k) +2 (5i+3j-2k) -c =0
6i +3j -9k +10i +6j -4k -c=0
c = 16i +9j -13k
so it is answer
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