Physics, asked by PranitPawar, 16 days ago

Two vectors are of identical magnitude have their dot product as 32 and both are of magnitude 4 then they are inclined at an angle of—.
(A) 60°
(B)π/3
(C) cos-1(2)
(D)no such vectors exist​

Answers

Answered by snehal2711
0

Answer:

c) this is the answer

hope this will help you

Answered by shreemanlegendlive
4

Question :

Two vectors are of identical magnitude have their dot product as 32 and both are of magnitude 4 then they are inclined at an angle of—.

(A) 60°

(B)π/3

(C) cos-1(2)

(D)no such vectors exist

Formula :

Cross product of two vectors \tt \bar{a} \:and\: \bar{b}

\tt \bar{a}.\bar{b} = |\bar{a}||\bar{b}|cos\theta

Where \tt \theta : angle between two vectors.

Solution :

Let the two vectors be \tt \bar{a} \:and \: \bar{b}

\tt \bar{a}.\bar{b} = 32

\tt |\bar{a}| = |\bar{b}| = 4

\tt \bar{a}.\bar{b} = |\bar{a}||\bar{b}|cos\theta

\tt \implies 32 = (4)(4)cos\theta

\tt \implies 32 = 16cos\theta

\tt \implies cos\theta = 2

Since cosine function lies between [-1,1]

No such vectors are possible .

Option :

The correct option is option(D).

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