Question

Two vectors c and d have magnitudes 5 units and angle is 40 with each other

Answer 1

Answer:

$resultant = \sqrt{ {c}^{2} + {d}^{2} +2cdcos \alpha }$

where alpha is the angle between two vectors.

$= \sqrt{ {5}^{2} + {5}^{2} + 2 \times 5 \times 5 \cos(40) }$

$\sqrt{25 + 25 + 50 \times 0.76}$

$\sqrt{50 + 38}$

$\sqrt{88}$

9.4

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