TWO VECTORS, EACH OF MAGNITUDE 'A' COMBINES TO GIVE RESULTANT OF MAGNITUDE 'A' . THEN FIND THE ANGLE BETWEEN TWO VECTORS AND THE ANGLE OF RESULTANT.
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The magnitude of resultant of two vectors P and Q is given by,
R = √[P² + Q² + 2PQ cos θ]
According to the question, P = Q = R = A. Then,
A = √[A² + A² + 2A² cos θ]
A² = 2A² + 2A² cos θ
A² + 2A² cos θ = 0
A²(1 + 2 cos θ) = 0
Since A ≠ 0,
1 + 2 cos θ = 0
cos θ = - 1 / 2
=> θ = 120°
Hence angle between the two vectors is 120°.
The angle of resultant of two vectors P and Q is given by,
tan α = Q sin θ / (P + Q cos θ)
Hence here,
tan α = A sin 120° / (A + A cos 120°)
tan α = sin 120° / (1 + cos 120°)
tan α = (√3 / 2) / (1 - (1 / 2))
tan α = (√3 / 2) / (1 / 2)
tan α = √3
=> α = 60°
Hence angle of resultant is 60°.
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