two vectors each of magnitude a have A resultant of same magnitude A the angle between the two vectors is
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120 degree bcz at 120 degree value of cos is -1/2
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A^2 = A^2 + A^2 + 2 A^2 COS THETA
A^2 - 2 A^2 = 2 A COS THETA
-A^2 = 2 A COS THETA
-A^2 / 2 A = COS THETA
COS THETA=-1/2
THETA=120 DEGREE
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