Question

Two vectors have A and B have magnitudes 8 units and 12 units respectively. Their resultant is perpendicular to A. Find the angle between the vector
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Answer 1

Explanation:

1. Case 1: when angle between them is 0 degree:

then |A-BI=√√62 +82. =√100 2*6*8* Cos (0) 96 (Since Cos(0)=1)

=2 Units.

2. Case 2: When angle between them is 180 degree:

then |A-BI

62 +82 2*6*8* Cos (180)

=√100 +96 Cos(180) is -1)

= 14 Units.

3. Case 3: Case 3 is same as case 2. So the answer is same.

4. Case 4: When the angle between them is 120 degree.

then |A-BI = 62 +82 2*6* 8 * Cos(120)

100 + 48

Cos(120)= -1/2)

=12.16 Units.