two vectors have magnitude 2 metre and 3 metre.The angle between them is 60°.Find
a) the scalar product of two vector.
b) magnitude of their vector product.
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Answered by
87
HELLO THERE!
Let the two vectors be A and B.
According to your question,
|A| = 2m
|B| = 3m
Angle between them is 60°, so θ = 60°
Now,
(a) Scalar (DOT) product:
A.B = |A| |B| cos θ
= 2 x 3 x cos 60°
= 6 x 1/2
= 3
(ii) Vector (CROSS) product:
A x B = |A| |B| sin θ
= 2 x 3 x sin 60°
= 6 x √3/2
= 3√3
THESE ARE YOUR ANSWERS.
Thanks!
harshbhardwaj23:
thanks
Answered by
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this is the best answer
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