Two vectors have magnitude 3 and 4 units respectively.What should be the angle between them if the magnitude of the resultant is 1 unit
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Howdy!!
your answer is ----
LET,vector A = 3 unit and vector B = 4unit
Given, their resultant is 1 unit .
alos, let angle between them is ∅
so √A^2+B^2+2ABcos∅ = 1
=> A^2+B^2+2ABcos∅ = 1
=> 3^2 + 4^2 + 2×3×4cos∅ = 1
=> 9+16+24cos∅ = 1
=> 25+24cos∅ = 1
=> cos∅ = -24/24
=> cos∅ = -1
=> cos∅ = cos180°. [ cos180° = -1 ]
=> ∅ = 180°
hence, angle between two vectors is 180°
=================================
hope it help you
your answer is ----
LET,vector A = 3 unit and vector B = 4unit
Given, their resultant is 1 unit .
alos, let angle between them is ∅
so √A^2+B^2+2ABcos∅ = 1
=> A^2+B^2+2ABcos∅ = 1
=> 3^2 + 4^2 + 2×3×4cos∅ = 1
=> 9+16+24cos∅ = 1
=> 25+24cos∅ = 1
=> cos∅ = -24/24
=> cos∅ = -1
=> cos∅ = cos180°. [ cos180° = -1 ]
=> ∅ = 180°
hence, angle between two vectors is 180°
=================================
hope it help you
Avinashk111:
thanks
Answered by
0
here a=3,b=4. a^2+b^2+2abcosx=R^2. 9+16+24cosx=1.
24cosx=-24
cosx=-1
x=180°
24cosx=-24
cosx=-1
x=180°
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