Two vectors have magnitudes 2 m and 3 m. The angle between them is 60°. Find
(a) The scalar product of the two vectors,
(b) The magnitude of their vector product.
Concept of Physics - 1 , HC VERMA , Chapter - "Physics and Mathematics"
Answers
Answered by
2
Thanks for asking the question!
ANSWER::
Given:-
Magnitude of a vector =2 m
Magnitude of b vector =3 m
Angle between the vectors = 60°
(a) The scalar product of the two vectors = a.b = |a| . |b| cos Ф = |a| . |b| cos 60° = 2 x 3 x 1/2 = 3 m²
(b) The magnitude of their vector product = |axb| = |a| . |b| sin Ф = |a| . |b| sin 60° = 2 x 3 x √3/2 = 3√3 m²
Hope it helps!
ANSWER::
Given:-
Magnitude of a vector =2 m
Magnitude of b vector =3 m
Angle between the vectors = 60°
(a) The scalar product of the two vectors = a.b = |a| . |b| cos Ф = |a| . |b| cos 60° = 2 x 3 x 1/2 = 3 m²
(b) The magnitude of their vector product = |axb| = |a| . |b| sin Ф = |a| . |b| sin 60° = 2 x 3 x √3/2 = 3√3 m²
Hope it helps!
Similar questions