Physics, asked by amipatel111, 10 months ago

Two vectors have magnitudes 2 m and 3m. The angle between them is 60°. Find (a) the scalar product of the two vectors, (b) the magnitude of their vector product.

Answers

Answered by Anonymous
3

Answer:

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Explanation:

Let the two vectors be A and B.

According to your question,

|A| = 2m

|B| = 3m

Angle between them is 60°, so θ = 60°

Now,

(a) Scalar (DOT) product:

A.B = |A| |B| cos θ

= 2 x 3 x cos 60°

= 6 x 1/2

= 3

(ii) Vector (CROSS) product:

A x B = |A| |B| sin θ

= 2 x 3 x sin 60°

= 6 x √3/2

= 3√3

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Answered by rithvik301
3

Answer:

Explanation:

Let the two vectors be A and B.

|A| = 2m

|B| = 3m

Angle between them is 60°, so θ = 60°

(a) Scalar (DOT) product:

A.B = |A| |B| cos θ

= 2 x 3 x cos 60°

= 6 x 1/2

= 3

(ii) Vector (CROSS) product:

A x B = |A| |B| sin θ

= 2 x 3 x sin 60°

= 6 x √3/2

= 3√3

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