Two vectors have magnitudes 2 m and 3m. The angle between them is 60°. Find (a) the scalar product of the two vectors, (b) the magnitude of their vector product.
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Answered by
3
Answer:
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Explanation:
Let the two vectors be A and B.
According to your question,
|A| = 2m
|B| = 3m
Angle between them is 60°, so θ = 60°
Now,
(a) Scalar (DOT) product:
A.B = |A| |B| cos θ
= 2 x 3 x cos 60°
= 6 x 1/2
= 3
(ii) Vector (CROSS) product:
A x B = |A| |B| sin θ
= 2 x 3 x sin 60°
= 6 x √3/2
= 3√3
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Answered by
3
Answer:
Explanation:
Let the two vectors be A and B.
|A| = 2m
|B| = 3m
Angle between them is 60°, so θ = 60°
(a) Scalar (DOT) product:
A.B = |A| |B| cos θ
= 2 x 3 x cos 60°
= 6 x 1/2
= 3
(ii) Vector (CROSS) product:
A x B = |A| |B| sin θ
= 2 x 3 x sin 60°
= 6 x √3/2
= 3√3
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