Question

two vectors having magnitude 12 and 13 are inclined at an angle of 45° with the other . find their resultant vector..​

Answer 1

HEY MATE..

HERE'S THE ANSWER..

_______________________

We know....

a = 12 ; b = 13 ; R = ? ; Q = 45°

=> R = √ ( a^2 + b^2 + 2 a . b . cos Q )

=> R = √ ( 12^2 + 13^2 + 2 . 12 . 13. cos 45 ° )

=> R = = √[144  + 169  + 312 (1/√2)]

=> R = √(313  + 220.65)

=> R = √(533.65)

=> R = 23.10

HOPE HELPED..

HAVE A NICE DAY..

:-)

Answer 2

Explanation:

a=12,b=13 ,R=?,angle=45 degree r=a2+b2+2abcosthita,=144+169+2×12×13cos45 degree,=144+169+312×1/2,=23.1