two vectors having magnitude 12 and 13 inclined at an angle 45 degree to each other find the resultant vector
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Answered by
360
HEY MISS ..
HERE'S THE ANSWER..
_______________________
We know....
a = 12 ; b = 13 ; R = ? ; Q = 45°
=> R = √ ( a^2 + b^2 + 2 a . b . cos Q )
=> R = √ ( 12^2 + 13^2 + 2 . 12 . 13. cos 45 ° )
=> R = = √[144 + 169 + 312 (1/√2)]
=> R = √(313 + 220.65)
=> R = √(533.65)
=> R = 23.10
HOPE HELPED..
HAVE A NICE DAY..
:-)
HERE'S THE ANSWER..
_______________________
We know....
a = 12 ; b = 13 ; R = ? ; Q = 45°
=> R = √ ( a^2 + b^2 + 2 a . b . cos Q )
=> R = √ ( 12^2 + 13^2 + 2 . 12 . 13. cos 45 ° )
=> R = = √[144 + 169 + 312 (1/√2)]
=> R = √(313 + 220.65)
=> R = √(533.65)
=> R = 23.10
HOPE HELPED..
HAVE A NICE DAY..
:-)
Answered by
208
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