Question

Two vectors of equal magnitude a with angle theta between them the magnitude of their resultant is

Answer 1

Answer:

$2a \cos \: \frac{theata}{2}$

is the correct answer

Answer 2

Answer is ​θ = θ/2

We have,

Two vectors having equal magnitude makes an ∠θ

Let the magnitude of each vector be A is:

R= √(A²+A²+2A×Acosθ)

​= √[2A²(1+cosθ)]

=​√2A²×2cosθ/2

​=2Acosθ/2

​Now,

Direction : Let angle between any one of vectors and the resultant be θ

tanθ= Asinθ/Acosθ+A

= SinФ/1+cosθ

=2sinθ/2cosθ/2 ÷ 2cos²θ/2

​By using,

sinθ = 2sinθ/2cosθ/2 and 1

= cosθ = 2cos²θ/2

= tanθ/2

means that

tanθ = tanθ/2

​θ = θ/2

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