two vectors of equal magnitude have a resultant
equal to either of them in magnitude. The angle
between them is :
(1) 60° (2) 90° (3) 105° (4) 120°
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here is the solution of ur problem
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ATQ
a(→) + a(→) = √ a²+ a²+2a²cosθ
but
given that
√ (a²+ a²+2a²cosθ) = a
=> 2a²+2a²cosθ= a²
=> 1+cosθ = 1/2
=> cosθ = -1/2
=> cosθ = cos120°
=> θ= 120°
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