Question

Two vectors of magnitude 10N and 5N are acting on a particleof mass 2 kg...The 2 forces are inclined 30 degrees angle...find the acceleration of particle????answer correctly.. only known can answer plzzz very urgent​

Answer 1

For Diagram Refer the Attachment

From the figure it is clear that

5sin@ Balances The Normal Reaction force

And 5 cos@ along with 10 N forces makes the acceleration

$5Cos(\theta )=5\times Cos(30°)=\frac{5\sqrt{3}}{2}$

Hence Total force acting is

$10+\frac{5\sqrt{3}{2}=\frac{20+5(1.732)}{2}$

$\frac{20+8.66}{2}=\blue{14.33}$

Total force is 14.33 N

Acceleration is guven by

We Know that

Force =m× acc

or

$acc=\frac{F}{Mass}=\frac{14.33}{2}$

$\huge{Acc.=7.165}$

Answer 2

$\huge\mathfrak\blue{Answer:}$

Given:

• We have been given two vectors of Magnitude 10N and 5N having an angle of 30° between them
• Both forces are acting upon a mass of 2kg

To Find:

• We have to find the acceleration of the body on which force are acting

Solution:

We have been given that 2 Force are

$\sf{First \: Force \: ( F_1 ) = 10 N}$

$\sf{Second\: Force \: ( F_2 ) = 5 N}$

$\sf{Angle \: Between \: them \: ( Θ ) = 30°}$

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Resultant of both force vector can be calculated by using the Formula:

$\boxed{\sf{\red{|F_{net}|= \sqrt{ {|F_1|}^2 + {|F_2|}^2 + 2 \: |F_1| \: |F_2| \: cos \: Θ}}}}$

Substituting the values

$\implies \sf{|F_{net}| = \sqrt{ 10^2 + 5^2 + 100 \: cos \: 30°}}$

$\implies \sf{|F_{net}| = \sqrt{ 100 + 25 + 100 \: cos \: 30°}}$

$\implies \sf{|F_{net}| = \sqrt{ 125 + 100 \times \frac{\sqrt{3}}{2}}}$

$\implies \sf{|F_{net}| = \sqrt{ 125 + 50\sqrt{3}}}$

$\implies \sf{|F_{net}| = 5\sqrt{ 5 + 2\sqrt{3}}}$

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$\underline{\large\mathfrak\orange{We \: know \: that \: Force \: is \: given \: by}}$

Using Second law of motion we know that Force is given by Formala:

$\implies \boxed{\sf{F_{net} = m \times a}}$

$\implies \sf{2 \times a = 5\sqrt{ 5 + 2\sqrt{3}}}$

$\implies \sf{2a = 5\sqrt{ 5 + 2\sqrt{3}}}$

$\implies \sf{a = \dfrac{5\sqrt{ 5 + 2\sqrt{3}}}{2} \quad m/s^2}$

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$\huge\underline{\sf{\red{A}\orange{n}\green{s} \pink{w}\blue{e} \purple{r}}}$

$\large\boxed{\sf{\purple{Acceleration \: of \: Body = \dfrac{5\sqrt{ 5 + 2\sqrt{3}}}{2}} \: }}$

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