two vectors p and q have magnitude 3 and 4 units respectively.R is the resultant of p and q the angle between them is 30 degree find magnitufe and direction of R
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→ R = √(p^2+q^2+2pq Cos 30° )
→ R = √ ( 9 + 16 + 24 Cos 30° )
→ R = √ ( 25 + 12√3 )
→ R = 6.76
Suppose, the angle between p and R is y
So, → y = tan^-1 ( q sinx / q cosx + p)
→ y = tan^-1 ( 4 sin 30° / (4 cos 30° + 3) )
→ y = 17.19°
Therefore the The magnitude of R = 6.76 Unit and direction of it is 17.19° away from the vector p ( towards q vector )
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