Question

Two vehicles (A and B) having mass 400 kg and 600 kg respectively, have occupied the same surface area on a road. Compare the pressure exerted by the vehicles on the surface.​

Answer 1

Answer:

200 kg is pressure exerted by the vehicles on the surface..

Explanation:

Not sure about the answer..

Answer 2

Given :

• Mass of Vehicle A = 400 kg
• Mass of Vehicle B = 600 kg
• Contact area of A = Contact area of B

To Find :

• The Comparison Of Pressure of the two Vehicles exerted on the ground

Let's Assume :

And will Assume the surface area of Contact of Both Vehicle A and B is 'y'

Concept :

We will firstly Assume the surface area of Contact of the vehicles (See the let's Assume part).

Now, as the Force acting on the the Vehicles will be their weight (mass×g).

Then, we will use the formula of Pressure to find the Pressure:

• P= F/A

Then, we can compare their Pressure

Solution :

Mass of A = 400 kg

Mass of B = 600 kg

Surface area of Contact = y

So, weight (Force acting on Ground) :

1] Of A :

Weight = mass × g

= 400 kg × 10m/s²

= 4000 N

2] Of B :

Weight = mass × g

= 600 × 10m/s²

= 6000 N

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Now, Force of A = 4000 N

Force of B = 6000 N

Surface area of Contact = y

So, now the pressure acting on A :

$\displaystyle \rm \implies p = \frac{f}{a}$

$\displaystyle \rm \implies p_a = \frac{4000}{y}$

Now, Force acting on B :

$\displaystyle \rm \implies p_b = \frac{6000}{y}$

Comparison:

Now, we will compare the pressures :

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1] Ratio Comparison :

We will compare the ratio :

A : B

= 4000/y : 6000/y

= 4000 : 6000

= 4 : 6

= 2 : 3

So, we get that:

A = ⅔B

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2] Difference Comparison:

We will compare it with Difference:

B-A

= 6000/y - 4000/y

= (6000-4000)/y

= 2000/y

So, B-A = 2000/y