Question

Two vehicles start from a point and travel along a circular road of length 150 meters in
the opposite direction. Vehicle V1 travels at constant speed of 5 m/s. Vehicle V2 starts from rest and travels at constant acceleration of 2 m/s2. After how many seconds from start will they cross each other the second time?

Answer 1

Distance traveled by car A=S

A

Distance traveled by car B=S

B

According to formula S=ut+

2

1

at

2

S

A

=0t+

2

1

×2t

2

S

B

=10t+

2

1

×0t

2

Car A will overtake car B when

S

A

=S

B

+100

Putting the value S

A

and S

B

+2=10t+100

+2−10t−100=0

After solving for t, we get

t=16.18sec possible

t=−6.10sec not possible

Answer 2

Answer:

After 10 seconds from start will the vehicles cross each other.

Explanation:

Distance travelled by car A=S₁

Distance travelled by car B=S₂

Using the formula,

$s=ut+1/2at^{2}$

For A,

$S1=10t$

For B,

$S2=t^{2}$

The vehicles will cross each other, when

S₁=S₂

10t=t²

10=t²/t

∴t=10

Thus, After 10 seconds from start will the vehicles cross each other.