Question

Two velocities 15m/s and 20m/s are inclined at an angle 60°to each other, obtain the resultant Velocity: graphical method,by analytics method

Answer 1

Answer:

| R | = √(A² + B² + 2ABcosØ)

Here, A = 15 m/s, B = 20 m/s and Ø = 60⁰

=> | R l = √(15² + 20² + 2×15×20cos60⁰)

=> | R | = √(225 + 400 + 300)

=> | R | = √(925)

=> | R | = 30.41 m/s

Therefore, the resultant is 30.41 m/s

Answer 2

Given :

• velocities : 15m/s and 20m/s
• Given angle = 60°
• Resultant = ??

We know that,

|R|² = A² + B² + 2ABCosΘ

• Let A be 15m/s and B be 20m/s
• theta = 60°
• cos 60° = 1/2

|R|² = 15² + 20² + 2 × 15 × 20 × cos 60°

|R|² = 225 + 400 + 600 × 1/2

|R|² = 625 + 300

|R| = √925

|R| = 30.4

Hence,

• Resultant = 30.4m/s