Two vertical poles of height 20m and 15m are placed 12m apart. what is the distance between their top ends
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Answer:
13 m
Step-by-step explanation:
From figure, EB = DC = 15 m
AE = AB - EB
AE = 20 - 15
AE = 5m
BC = ED = 12 m
therefore in ∆AED,
AD² = AE² + ED²
= 5² + 12²
= 25 + 144
AD² = 169
AD = 13 m
thus, the distance between their top ends is 13 m
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