Two vertical poles of heights “a” m and “b” m stand apart on a horizontal plane. The height (in meters) of the point of intersection of the lines joining the top of each pole to the foot of the other from this horizontal plane is
Answers
Given : Two vertical poles of heights “a” m and “b” m stand apart on a horizontal plane.
To find : The height (in meters) of the point of intersection of the lines joining the top of each pole to the foot of the other from this horizontal plane
Solution:
Refer attached diagram
xz = m
yz = n
xy = d
PZ = y
PZ ║ Poles
Hence
m/d = y/b
n/d = y/a
Adding both
=> m/d + n/d = y/b + y/a
=> (m + n)/d = y (a + b)/ab
=> d/d = y (a + b)/ab
=> 1 = y (a + b)/ab
=> y = ab/(a + b)
The height (in meters) of the point of intersection of the lines joining the top of each pole to the foot of the other from this horizontal plane is ab/(a + b)
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