Two vertical poles of length a and b subtend the same angle 45° at a point on the line joining their feet. Then the square of the distance between their tops is:
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Two vertical poles of length a and b subtend the same angle 45° at a point on the line joining their feet. Then the square of the distance between their tops is: = 2 (a² + b²)
Step-by-step explanation:
Assumption point lies between the poles
Angle subtended = 45°
Tan45° = Perpendicular / Base
Tan 45° = 1
so perpendicular = base
height of pole = distance of foot of pole from point
Point is at a distance from foot of pole a
& Point is at b distance from pole b
Horizontal Distance between pole = a+b
Vertical distance between top of poles = |a - b|
square of Distance between top poles = ( a + b)² + (|a-b|)²
= a² + b² + 2ab + a² + b² - 2ab
= 2 (a² + b²)
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