Question

Two vertices of a rectangle are 6, -1), (6,9) and
remaining two vertices are on Y-axis, then find the
area of rectangle
​

Answer 1

Answer:

60 sq. units

Step-by-step explanation:

see the above attached image for the solution

Answer 2

Answer:

Area of the Rectangle is 60 unit².

Step-by-step explanation:

Given:

Vertices of rectangle ( 6 , -1 ) and ( 6 , 9 ).

Remaining two are at y-axis.

To find: Area of the rectangle.

Marking given vertices on graph and using property of rectangle that all angles are right angles.

We get, Coordinates of the remaining vertex on y-axis are ( 0 , -1 ) and ( 0 , 9 )

Figure is attached.

⇒ Length, AB = $\sqrt{(6-0)^2+(-1-(-1))^2}=\sqrt{6^2+(-1+1)^2}=\sqrt{6^2+0^2}=6$

⇒ Breadth, CB = $\sqrt{(6-6)^2+(9-(-1))^2}=\sqrt{0^2+(9+1)^2}=\sqrt{0^2+10^2}=10$

Area of the rectangle =  AB × CB

                                     = 6 × 10

                                     = 60 unit²

Therefore, Area of the Rectangle is 60 unit².