Question

two vertices of a triABC are given by A(6,4) B(-2,2) and the centroid is G(3,4). Find the coordinates of it's third vertex C

Answer 1

to find centroud formula is :
(x1 +x2+x3/3 , y1+ y2+y3/3)
so
( 4 -2 +x3 , 4+2 +y3 ) = ( 3,4)

4-2 +x3 = 3 and 4 +2 + y3 = 4
2 + x3 =3 and 6 + y3 = 4
x3 = 3-2 and y3 = 4-6
x3 = 1 and y3 = -2

so co ordinate of vertex C ( 1,-2)
hope it is helpful.........
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