Question

two vertices of a triangle are (1,2), (3,5), and the centeroid is at the origin. Find the third vertex.

Find the coordinates (x,y) of a point whose distance from points (3,5) is 5 units & that from (0,1) is 10 units , given that 3x=2y

If 3b is the length of a side of an equilateral triangle ABC ,base BC lies on x-axis & B lies of origin , find the coordinate of vertices of ABC

Answer 1

According to question

two vertices of triangle
A = (1, 2) 
B = (3, 5)
Also centroid   O = (0, 0)

Let the third vertex be (x, y)

Then 
x + 1 + 3 / 3 = 
so    x= -4
and
y + 2 + 5 / 3 = 0
So   y = -7
Thus

Third vertex   C = (-4, -7)

Answer 2

Answer:ugg

Step-by-step explanation: