two vertices of A triangle are (-1, 4) and (5, 2). if the centroids is (0, 3)
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Answer:
Let the △ABC has vertices A=(x
1
,y
1
)=(−1,4),B=(x
2
,y
2
)=(5,2) and C=(x
3
,y
3
).
The centroid G=(
3
x
1
+x
2
+x
3
,
3
y
1
+y
2
+y
3
)=(0,−3)
Therefore,
3
−1+5+x
3
=0
⇒x
3
=−4
Also
3
4+2+y
3
=−3
⇒y
3
=−15
∴C=(x
3
,y
3
)=(−4,−15)
Step-by-step explanation:
your answer
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