two vertices of a triangle are (3 -5) and (-7 4).if its centroid is (2 -1) find the third vertex
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Answer:
the third side is (10,-2)
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Given : (2 , - 1 ) is the centroid of the triangle with (3 -5) and (-7 4) as the two vertices
To find : the third vertex
Solution:
Centroid (x , y ) = ( ( x₁ + x₂ + x₃) /3 , (y₁ + y₂ + y₃) /3 )
Centroid (x , y ) = (2 , - 1)
A = (3,-5)
B = (-7, 4)
C = (Cx , Cy )
=> 2 = ( 3 - 7 + Cx)/ 3 => Cx = 10
-1 = ( -5 + 4 + Cy)/3 => Cy = -2
Hence third vertex is ( 10 , - 2 )
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