Two vertices of a triangle are (-3,5) and (7, - 4). If its centroid is (2, - 1), then the third vertex is
(a) (2, 4)
(b)(-2,4)
(c) (2, - 4)
(d) (-2,-4)
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Let P(3,-5) and Q(-7,4) be the two vertices of a triangle . Centroid of a triangle is
G(2,-1).
The coordinates of the centroid of △ABC is (x1+3-7/2 , y1-5+4/3) = (2,1)
(x1-4/3 , y1-1/3) = (2,-1)
x1 = 6+4, y1 = -3+1
x1 = 10, y1 = -2
∴ The third vertex is (10,2).
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