Two vertices of a triangle are 8 -6 and -4 6 the area of a triangle is 120 sq.units find the third vertex if it lies on x-2y=3
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Area of triangle with vertices (x,y),(8,-6)&(-4,6) is
X(-12) +8(6-y)-4(y+6)=240 absolute
-12x-12y=216
X+y=_18
X-2y=3
So 3y==-21
Y =-7
X=-11
X(-12) +8(6-y)-4(y+6)=240 absolute
-12x-12y=216
X+y=_18
X-2y=3
So 3y==-21
Y =-7
X=-11
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