Question

Two vertices of an equilateral triangle are (0,3) and (4,3). Find the third vertex of the triangle​

Answer 1

Answer:3

Step-by-step explanation: By using distance formula side AB=

(0-4)^2 +(3-3)^2 whole root

16roit

=4

Now all side of equilateral triangle is equal

So let sideAB=BC=AC and also let side AC(X, Y)

Ac=(0-X)^2 +(3-y)^2 whole under root

(4)^2 =X^2 +Y^2 +9-6Y

X^2 +Y^2 - 6y+9-16=0

X^2+ Y^2 - 6Y-7=0. . . . . (1)

Again side BC Distance

(4) ^2=(4-x)^2 +(3-y)^2

16=16+X^2 - 8X+9+y^2 - 6y

X^2 - 8X+y^2 +9-6y=0. . . .( 2)

Now from 1, 2 equation

X^2 +y^2 - 6y-7=X^2 - 8X+Y^2 +9-6y

X=2. . . By calculate

Then on (1), (2) Y also be calculate

Y=-3+-2root3

Hence c(2,-3+-2root3

I hope this answer help you,

For any mistakes sorry.

On (1)substitute by using quadric equation

See, (2)^2 +Y^2 - 6y-7

y^2 - 6Y-3

-6+-whole under root 36+12/2*1

=-3+-2under root 3

hope this answer helped u

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Answer 2

See these attachments u will find ur Answer ↑↑↑

@Itzbeautyqueen23

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