Question

Two vertices of an isosceles triangle are (2,0) and (2,5). Find the third vertex if the lrngth of equal sides is 3 units

Answer 1

Step-by-step explanation:

$\sqrt{(x {}^{2} } - {x}^{1} ) + ( {y}^{2} - {y}^{1} )$

use this formula

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Answer 2

Answer:

(3.66,2.5) or (0.34,2.5)

Step-by-step explanation:

distance between given points is 5 so it's unequal side.

let point be x,y

(x-2)^2 + (y-0)^2 = (x-2)^2 + (y-5)^2.

(distance equal from both points)

on solving:

y=2.5

(x-2)^2 + y^2 =9 ( equal side =3)

put y = 2.5

on solving

x= 3.66 and x= 0.34